To start a service with the command line, use these steps:

[Fix] Error 1053: The service did not respond to the start or control request in a timely fashion

1. Change timeout settings via registry editor.
2. Check for system file issues.
3. Get Ownership of the application.
4. Update windows.
5. Protect your online privacy with a VPN client.
6. Data recovery tools can prevent permanent file loss.

Solution 1: Changing Timeout Settings through Registry

1. Now, search for the key of ‘ServicesPipeTimeout’.
2. Name the key as ‘ServicesPipeTimeout’ and set the value as 180000 (You can also right-click the value and click Modify if the option to set the value didn’t come in your case.
3. Save changes and exit.

SOLUTION

1. Go to Start > Run > and type regedit.
2. Navigate to: HKEY_LOCAL_MACHINE/SYSTEM/CurrentControlSet/Control.
3. With the control folder selected, right click in the pane on the right and select new DWORD Value.
4. Name the new DWORD: ServicesPipeTimeout.
5. Right-click ServicesPipeTimeout, and then click Modify.

Run Windows Services manager (launch services. msc from the Start menu). Right-click on the service you would like to configure, and select Properties. On the General tab, change the Startup type to Automatic (Delayed Start), as shown in Fig.

1. Open Start.
2. Search for Command Prompt, right-click the top result, and select the Run as administrator option.
3. Type the following command to start a service and press Enter: net start “SERVICE-NAME”

FAQ

1. Right-click the taskbar and choose “Task Manager“.
2. Select the “Services” tab.
3. Right-click the service you wish to delete, then choose “Go to details“.
4. The process related to the service is highlighted. If you wish to remove it, you can track it down by right-clicking it and selecting “Open file location“.

When a service starts, it communicates to the Service Control Manager how long it has to start in what’s called the service’s timeout period. If the Service Control Manager does not receive a “service started” notice from the service within this timeout period, it will terminate the process that hosts the service.

What causes the SP-1503 and SP-0152 errors? The issue is majorly seen in the systems where multiple Oracle Installations are done. For example, I have seen one Client having Oracle Database Software 11g (64-bit), Oracle Client 11g (64-bit), 10g (32-bit) installed on a single system to connect to remote databases.

This error is caused when you try to assign a variable of type “integer” to a variable of type “string”. Error this example presents: error CS1503: Argument `#1′ cannot convert `___’ expression to type `___’

This error message is the cause of a timeout that occurs after a request was initiated to start a service but it did not respond in the time window. Error 1053: The Service did not Respond to the Start or Control Request in a Timely Fashion. There are numerous variations of the error message ranging from issues in Windows services